-(5/w-3)=-(5/4w-12)+1

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Solution for -(5/w-3)=-(5/4w-12)+1 equation:


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

-(5/w-3) = 1-((5/4)*w)+12 // - 1-((5/4)*w)+12

(5/4)*w-(5/w)-12-1+3 = 0

(5/4)*w-5*w^-1-12-1+3 = 0

5/4*w^1-5*w^-1-10*w^0 = 0

(5/4*w^2-10*w^1-5*w^0)/(w^1) = 0 // * w^2

w^1*(5/4*w^2-10*w^1-5*w^0) = 0

w^1

(5/4)*w^2-10*w-5 = 0

(5/4)*w^2-10*w-5 = 0

DELTA = (-10)^2-(-5*4*(5/4))

DELTA = 125

DELTA > 0

w = (125^(1/2)+10)/(2*(5/4)) or w = (10-125^(1/2))/(2*(5/4))

w = 2/5*(5*5^(1/2)+10) or w = 2/5*(10-5*5^(1/2))

w in { 2/5*(10-5*5^(1/2)), 2/5*(5*5^(1/2)+10)}

w in { 2/5*(10-5*5^(1/2)), 2/5*(5*5^(1/2)+10) }

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