-(5s+2)=4(s+1)

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Solution for -(5s+2)=4(s+1) equation: 



-(5s+2)=4(s+1)

We move all terms to the left:

-(5s+2)-(4(s+1))=0

We get rid of parentheses

-5s-(4(s+1))-2=0



We calculate terms in parentheses: -(4(s+1)), so:

4(s+1)

We multiply parentheses

4s+4

Back to the equation:

-(4s+4)



We get rid of parentheses

-5s-4s-4-2=0

We add all the numbers together, and all the variables

-9s-6=0

We move all terms containing s to the left, all other terms to the right

-9s=6

s=6/-9

s=-2/3

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