-(5v+1)=6v-3(v-5)

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Solution for -(5v+1)=6v-3(v-5) equation:



-(5v+1)=6v-3(v-5)
We move all terms to the left:
-(5v+1)-(6v-3(v-5))=0
We get rid of parentheses
-5v-(6v-3(v-5))-1=0
We calculate terms in parentheses: -(6v-3(v-5)), so:
6v-3(v-5)
We multiply parentheses
6v-3v+15
We add all the numbers together, and all the variables
3v+15
Back to the equation:
-(3v+15)
We get rid of parentheses
-5v-3v-15-1=0
We add all the numbers together, and all the variables
-8v-16=0
We move all terms containing v to the left, all other terms to the right
-8v=16
v=16/-8
v=-2

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