-(5v+1)=6v-3(v-5)

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Solution for -(5v+1)=6v-3(v-5) equation: 



-(5v+1)=6v-3(v-5)

We move all terms to the left:

-(5v+1)-(6v-3(v-5))=0

We get rid of parentheses

-5v-(6v-3(v-5))-1=0



We calculate terms in parentheses: -(6v-3(v-5)), so:

6v-3(v-5)

We multiply parentheses

6v-3v+15

We add all the numbers together, and all the variables

3v+15

Back to the equation:

-(3v+15)



We get rid of parentheses

-5v-3v-15-1=0

We add all the numbers together, and all the variables

-8v-16=0

We move all terms containing v to the left, all other terms to the right

-8v=16

v=16/-8

v=-2

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