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-(5x-2)(3-4x)=-2(3+x)
We move all terms to the left:
-(5x-2)(3-4x)-(-2(3+x))=0
We add all the numbers together, and all the variables
-(5x-2)(-4x+3)-(-2(x+3))=0
We multiply parentheses ..
-(-20x^2+15x+8x-6)-(-2(x+3))=0
We calculate terms in parentheses: -(-2(x+3)), so:We get rid of parentheses
-2(x+3)
We multiply parentheses
-2x-6
Back to the equation:
-(-2x-6)
20x^2-15x-8x+2x+6+6=0
We add all the numbers together, and all the variables
20x^2-21x+12=0
a = 20; b = -21; c = +12;
Δ = b2-4ac
Δ = -212-4·20·12
Δ = -519
Delta is less than zero, so there is no solution for the equation
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