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-(5y=3)-(-4y-5)=-1
We move all terms to the left:
-(5y-(3)-(-4y-5))=0
We calculate terms in parentheses: -(5y-3-(-4y-5)), so:We get rid of parentheses
5y-3-(-4y-5)
determiningTheFunctionDomain 5y-(-4y-5)-3
We get rid of parentheses
5y+4y+5-3
We add all the numbers together, and all the variables
9y+2
Back to the equation:
-(9y+2)
-9y-2=0
We move all terms containing y to the left, all other terms to the right
-9y=2
y=2/-9
y=-2/9
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