-(5z-(11z+1))=1+(5z+2)

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Solution for -(5z-(11z+1))=1+(5z+2) equation: 



-(5z-(11z+1))=1+(5z+2)

We move all terms to the left:

-(5z-(11z+1))-(1+(5z+2))=0



We calculate terms in parentheses: -(5z-(11z+1)), so:

5z-(11z+1)

We get rid of parentheses

5z-11z-1

We add all the numbers together, and all the variables

-6z-1

Back to the equation:

-(-6z-1)





We calculate terms in parentheses: -(1+(5z+2)), so:

1+(5z+2)

determiningTheFunctionDomain
(5z+2)+1

We get rid of parentheses

5z+2+1

We add all the numbers together, and all the variables

5z+3

Back to the equation:

-(5z+3)



We get rid of parentheses

6z-5z+1-3=0

We add all the numbers together, and all the variables

z-2=0

We move all terms containing z to the left, all other terms to the right

z=2

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