-(6)/(x-1)+(2-3x)/(x)=x

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Solution for -(6)/(x-1)+(2-3x)/(x)=x equation: 



-(6)/(x-1)+(2-3x)/(x)=x

We move all terms to the left:

-(6)/(x-1)+(2-3x)/(x)-(x)=0



Domain of the equation: (x-1)!=0

We move all terms containing x to the left, all other terms to the right

x!=1

x∈R





Domain of the equation: x!=0

x∈R



We add all the numbers together, and all the variables

-6/(x-1)+(-3x+2)/x-x=0

We add all the numbers together, and all the variables

-1x-6/(x-1)+(-3x+2)/x=0

We calculate fractions


-1x+(-6x)/(x^2-1x)+((-3x+2)*(x-1))/(x^2-1x)=0



We calculate terms in parentheses: +((-3x+2)*(x-1))/(x^2-1x), so:

(-3x+2)*(x-1))/(x^2-1x

We add all the numbers together, and all the variables

-1x+(-3x+2)*(x-1))/(x^2

We multiply all the terms by the denominator


-1x*(x^2+(-3x+2)*(x-1))

Back to the equation:

+(-1x*(x^2+(-3x+2)*(x-1)))



We multiply all the terms by the denominator


-1x*(x^2-1x)+(-6x)+((-1x*(x^2+(-3x+2)*(x-1))))*(x^2-1x)=0



We calculate terms in parentheses: +((-1x*(x^2+(-3x+2)*(x-1))))*(x^2-1x), so:

(-1x*(x^2+(-3x+2)*(x-1))))*(x^2-1x

We add all the numbers together, and all the variables

-1x+(-1x*(x^2+(-3x+2)*(x-1))))*(x^2

Back to the equation:

+(-1x+(-1x*(x^2+(-3x+2)*(x-1))))*(x^2)



We multiply parentheses

-x^3+1x^2+(-6x)+(-1x+(-1x*(x^2+(-3x+2)*(x-1))))*x^2=0

We get rid of parentheses

-x^3+1x^2-6x+(-1x+(-1x*(x^2+(-3x+2)*(x-1))))*x^2=0

We do not support expression: x^3

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