-(6-4c)+3c=10-2(c-1)

Solution for -(6-4c)+3c=10-2(c-1) equation:

Simplifying
-1(6 + -4c) + 3c = 10 + -2(c + -1)
(6 * -1 + -4c * -1) + 3c = 10 + -2(c + -1)
(-6 + 4c) + 3c = 10 + -2(c + -1)

Combine like terms: 4c + 3c = 7c
-6 + 7c = 10 + -2(c + -1)

Reorder the terms:
-6 + 7c = 10 + -2(-1 + c)
-6 + 7c = 10 + (-1 * -2 + c * -2)
-6 + 7c = 10 + (2 + -2c)

Combine like terms: 10 + 2 = 12
-6 + 7c = 12 + -2c

Solving
-6 + 7c = 12 + -2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2c' to each side of the equation.
-6 + 7c + 2c = 12 + -2c + 2c

Combine like terms: 7c + 2c = 9c
-6 + 9c = 12 + -2c + 2c

Combine like terms: -2c + 2c = 0
-6 + 9c = 12 + 0
-6 + 9c = 12

Add '6' to each side of the equation.
-6 + 6 + 9c = 12 + 6

Combine like terms: -6 + 6 = 0
0 + 9c = 12 + 6
9c = 12 + 6

Combine like terms: 12 + 6 = 18
9c = 18

Divide each side by '9'.
c = 2

Simplifying
c = 2