-(6x+12)=2(3-x)

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Solution for -(6x+12)=2(3-x) equation: 



-(6x+12)=2(3-x)

We move all terms to the left:

-(6x+12)-(2(3-x))=0

We add all the numbers together, and all the variables

-(6x+12)-(2(-1x+3))=0

We get rid of parentheses

-6x-(2(-1x+3))-12=0



We calculate terms in parentheses: -(2(-1x+3)), so:

2(-1x+3)

We multiply parentheses

-2x+6

Back to the equation:

-(-2x+6)



We get rid of parentheses

-6x+2x-6-12=0

We add all the numbers together, and all the variables

-4x-18=0

We move all terms containing x to the left, all other terms to the right

-4x=18

x=18/-4

x=-4+1/2

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