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-(6x-(9x+5))=5+(2x+1)
We move all terms to the left:
-(6x-(9x+5))-(5+(2x+1))=0
We calculate terms in parentheses: -(6x-(9x+5)), so:
6x-(9x+5)
We get rid of parentheses
6x-9x-5
We add all the numbers together, and all the variables
-3x-5
Back to the equation:
-(-3x-5)
We calculate terms in parentheses: -(5+(2x+1)), so:We get rid of parentheses
5+(2x+1)
determiningTheFunctionDomain (2x+1)+5
We get rid of parentheses
2x+1+5
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
3x-2x+5-6=0
We add all the numbers together, and all the variables
x-1=0
We move all terms containing x to the left, all other terms to the right
x=1
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