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-(6x-3)-(5x-5)+11=-12(x+11)+3
We move all terms to the left:
-(6x-3)-(5x-5)+11-(-12(x+11)+3)=0
We get rid of parentheses
-6x-5x-(-12(x+11)+3)+3+5+11=0
We calculate terms in parentheses: -(-12(x+11)+3), so:We add all the numbers together, and all the variables
-12(x+11)+3
We multiply parentheses
-12x-132+3
We add all the numbers together, and all the variables
-12x-129
Back to the equation:
-(-12x-129)
-11x-(-12x-129)+19=0
We get rid of parentheses
-11x+12x+129+19=0
We add all the numbers together, and all the variables
x+148=0
We move all terms containing x to the left, all other terms to the right
x=-148
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