-(6x-4)=40+3x

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Solution for -(6x-4)=40+3x equation: 



-(6x-4)=40+3x

We move all terms to the left:

-(6x-4)-(40+3x)=0

We add all the numbers together, and all the variables

-(6x-4)-(3x+40)=0

We get rid of parentheses

-6x-3x+4-40=0

We add all the numbers together, and all the variables

-9x-36=0

We move all terms containing x to the left, all other terms to the right

-9x=36

x=36/-9

x=-4

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