-(7)/(2w+4)=-(6)/(w+2)

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Solution for -(7)/(2w+4)=-(6)/(w+2) equation: 


D( w )

2*w+4 = 0

w+2 = 0

2*w+4 = 0

2*w+4 = 0

2*w+4 = 0 // - 4

2*w = -4 // : 2

w = -4/2

w = -2

w+2 = 0

w+2 = 0

w+2 = 0 // - 2

w = -2

w in (-oo:-2) U (-2:+oo)

-(7/(2*w+4)) = -(6/(w+2)) // + 6/(w+2)

6/(w+2)-(7/(2*w+4)) = 0

6/(w+2)-7*(2*w+4)^-1 = 0

6/(w+2)-7/(2*w+4) = 0

(-7*(w+2))/((2*w+4)*(w+2))+(6*(2*w+4))/((2*w+4)*(w+2)) = 0

6*(2*w+4)-7*(w+2) = 0

5*w+10 = 0

(5*w+10)/((2*w+4)*(w+2)) = 0

(5*w+10)/((2*w+4)*(w+2)) = 0 // * (2*w+4)*(w+2)

5*w+10 = 0

5*w+10 = 0 // - 10

5*w = -10 // : 5

w = -10/5

w = -2

w in { -2} 

w belongs to the empty set

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