-(7b-5)=-6(1+2b)+6

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Solution for -(7b-5)=-6(1+2b)+6 equation: 



-(7b-5)=-6(1+2b)+6

We move all terms to the left:

-(7b-5)-(-6(1+2b)+6)=0

We add all the numbers together, and all the variables

-(7b-5)-(-6(2b+1)+6)=0

We get rid of parentheses

-7b-(-6(2b+1)+6)+5=0



We calculate terms in parentheses: -(-6(2b+1)+6), so:

-6(2b+1)+6

We multiply parentheses

-12b-6+6

We add all the numbers together, and all the variables

-12b

Back to the equation:

-(-12b)



We get rid of parentheses

-7b+12b+5=0

We add all the numbers together, and all the variables

5b+5=0

We move all terms containing b to the left, all other terms to the right

5b=-5

b=-5/5

b=-1

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