-(7x-4)-(6x-5)+8=-14(x-1)-(2x+15)+3

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Solution for -(7x-4)-(6x-5)+8=-14(x-1)-(2x+15)+3 equation: 



-(7x-4)-(6x-5)+8=-14(x-1)-(2x+15)+3

We move all terms to the left:

-(7x-4)-(6x-5)+8-(-14(x-1)-(2x+15)+3)=0

We get rid of parentheses

-7x-6x-(-14(x-1)-(2x+15)+3)+4+5+8=0



We calculate terms in parentheses: -(-14(x-1)-(2x+15)+3), so:

-14(x-1)-(2x+15)+3

We multiply parentheses

-14x-(2x+15)+14+3

We get rid of parentheses

-14x-2x-15+14+3

We add all the numbers together, and all the variables

-16x+2

Back to the equation:

-(-16x+2)



We add all the numbers together, and all the variables

-13x-(-16x+2)+17=0

We get rid of parentheses

-13x+16x-2+17=0

We add all the numbers together, and all the variables

3x+15=0

We move all terms containing x to the left, all other terms to the right

3x=-15

x=-15/3

x=-5

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