-(8+10j)=6(-2j+3)

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Solution for -(8+10j)=6(-2j+3) equation: 



-(8+10j)=6(-2j+3)

We move all terms to the left:

-(8+10j)-(6(-2j+3))=0

We add all the numbers together, and all the variables

-(10j+8)-(6(-2j+3))=0

We get rid of parentheses

-10j-(6(-2j+3))-8=0



We calculate terms in parentheses: -(6(-2j+3)), so:

6(-2j+3)

We multiply parentheses

-12j+18

Back to the equation:

-(-12j+18)



We get rid of parentheses

-10j+12j-18-8=0

We add all the numbers together, and all the variables

2j-26=0

We move all terms containing j to the left, all other terms to the right

2j=26

j=26/2

j=13

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