-(8-2)=3+10(1-3x)

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Solution for -(8-2)=3+10(1-3x) equation: 



-(8-2)=3+10(1-3x)

We move all terms to the left:

-(8-2)-(3+10(1-3x))=0

We add all the numbers together, and all the variables

-(3+10(-3x+1))-6=0



We calculate terms in parentheses: -(3+10(-3x+1)), so:

3+10(-3x+1)

determiningTheFunctionDomain
10(-3x+1)+3

We multiply parentheses

-30x+10+3

We add all the numbers together, and all the variables

-30x+13

Back to the equation:

-(-30x+13)



We get rid of parentheses

30x-13-6=0

We add all the numbers together, and all the variables

30x-19=0

We move all terms containing x to the left, all other terms to the right

30x=19

x=19/30

x=19/30

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