-(8-3x)=-2(1-x)+6

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Solution for -(8-3x)=-2(1-x)+6 equation: 



-(8-3x)=-2(1-x)+6

We move all terms to the left:

-(8-3x)-(-2(1-x)+6)=0

We add all the numbers together, and all the variables

-(-3x+8)-(-2(-1x+1)+6)=0

We get rid of parentheses

3x-(-2(-1x+1)+6)-8=0



We calculate terms in parentheses: -(-2(-1x+1)+6), so:

-2(-1x+1)+6

We multiply parentheses

2x-2+6

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We get rid of parentheses

3x-2x-4-8=0

We add all the numbers together, and all the variables

x-12=0

We move all terms containing x to the left, all other terms to the right

x=12

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