-(8/9)x=-16

Solution for -(8/9)x=-16 equation:

-(8/9)x=-16

We move all terms to the left:

-(8/9)x-(-16)=0


Domain of the equation: 9)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(+8/9)x-(-16)=0

We add all the numbers together, and all the variables

-(+8/9)x+16=0

We multiply parentheses

-8x^2+16=0

a = -8; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·(-8)·16
Δ = 512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{512}=\sqrt{256*2}=\sqrt{256}*\sqrt{2}=16\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{2}}{2*-8}=\frac{0-16\sqrt{2}}{-16}
=-\frac{16\sqrt{2}}{-16}
=-\frac{\sqrt{2}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{2}}{2*-8}=\frac{0+16\sqrt{2}}{-16}
=\frac{16\sqrt{2}}{-16}
=\frac{\sqrt{2}}{-1}
$