-(8/x-5)=(x-2/4x-20)+(10/x-5)

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Solution for -(8/x-5)=(x-2/4x-20)+(10/x-5) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

-(8/x-5) = x-((2/4)*x)+10/x-20-5 // - x-((2/4)*x)+10/x-20-5

(2/4)*x-x-(8/x)-(10/x)+5+5+20 = 0

(2/4)*x-x-8*x^-1-10*x^-1+5+5+20 = 0

30*x^0-1/2*x^1-18*x^-1 = 0

(30*x^1-1/2*x^2-18*x^0)/(x^1) = 0 // * x^2

x^1*(30*x^1-1/2*x^2-18*x^0) = 0

x^1

(-1/2)*x^2+30*x-18 = 0

(-1/2)*x^2+30*x-18 = 0

DELTA = 30^2-(-18*4*(-1/2))

DELTA = 864

DELTA > 0

x = (864^(1/2)-30)/(2*(-1/2)) or x = (-864^(1/2)-30)/(2*(-1/2))

x = 30-(12*6^(1/2)) or x = 30-(-12*6^(1/2))

x in { 30-(12*6^(1/2)), 30-(-12*6^(1/2))} 

x in { 30-(12*6^(1/2)), 30-(-12*6^(1/2)) }

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