-(8b-5)+3(1+8b)=40

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Solution for -(8b-5)+3(1+8b)=40 equation: 



-(8b-5)+3(1+8b)=40

We move all terms to the left:

-(8b-5)+3(1+8b)-(40)=0

We add all the numbers together, and all the variables

-(8b-5)+3(8b+1)-40=0

We multiply parentheses

-(8b-5)+24b+3-40=0

We get rid of parentheses

-8b+24b+5+3-40=0

We add all the numbers together, and all the variables

16b-32=0

We move all terms containing b to the left, all other terms to the right

16b=32

b=32/16

b=2

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