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-(8x-3)-(3x-5)+11=-12(x-1)-(2x+11)+3
We move all terms to the left:
-(8x-3)-(3x-5)+11-(-12(x-1)-(2x+11)+3)=0
We get rid of parentheses
-8x-3x-(-12(x-1)-(2x+11)+3)+3+5+11=0
We calculate terms in parentheses: -(-12(x-1)-(2x+11)+3), so:We add all the numbers together, and all the variables
-12(x-1)-(2x+11)+3
We multiply parentheses
-12x-(2x+11)+12+3
We get rid of parentheses
-12x-2x-11+12+3
We add all the numbers together, and all the variables
-14x+4
Back to the equation:
-(-14x+4)
-11x-(-14x+4)+19=0
We get rid of parentheses
-11x+14x-4+19=0
We add all the numbers together, and all the variables
3x+15=0
We move all terms containing x to the left, all other terms to the right
3x=-15
x=-15/3
x=-5
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