-(8x-5)=x+3(x-2)-29

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Solution for -(8x-5)=x+3(x-2)-29 equation: 



-(8x-5)=x+3(x-2)-29

We move all terms to the left:

-(8x-5)-(x+3(x-2)-29)=0

We get rid of parentheses

-8x-(x+3(x-2)-29)+5=0



We calculate terms in parentheses: -(x+3(x-2)-29), so:

x+3(x-2)-29

We multiply parentheses

x+3x-6-29

We add all the numbers together, and all the variables

4x-35

Back to the equation:

-(4x-35)



We get rid of parentheses

-8x-4x+35+5=0

We add all the numbers together, and all the variables

-12x+40=0

We move all terms containing x to the left, all other terms to the right

-12x=-40

x=-40/-12

x=3+1/3

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