-(9-3a)-(4+2a)-3=-(2-5)+(-a)+1

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Solution for -(9-3a)-(4+2a)-3=-(2-5)+(-a)+1 equation: 



-(9-3a)-(4+2a)-3=-(2-5)+(-a)+1

We move all terms to the left:

-(9-3a)-(4+2a)-3-(-(2-5)+(-a)+1)=0

We add all the numbers together, and all the variables

-(-3a+9)-(2a+4)-(-(-3)+(-1a)+1)-3=0

We get rid of parentheses

3a-2a-(-(-3)+(-1a)+1)-9-4-3=0



We calculate terms in parentheses: -(-(-3)+(-1a)+1), so:

-(-3)+(-1a)+1

determiningTheFunctionDomain
(-1a)+1-(-3)

We add all the numbers together, and all the variables

(-1a)+4

We get rid of parentheses

-1a+4

Back to the equation:

-(-1a+4)



We add all the numbers together, and all the variables

a-(-1a+4)-16=0

We get rid of parentheses

a+1a-4-16=0

We add all the numbers together, and all the variables

2a-20=0

We move all terms containing a to the left, all other terms to the right

2a=20

a=20/2

a=10

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