-(9-z)+3z=-3+4z-6

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Solution for -(9-z)+3z=-3+4z-6 equation: 



-(9-z)+3z=-3+4z-6

We move all terms to the left:

-(9-z)+3z-(-3+4z-6)=0

We add all the numbers together, and all the variables

-(-1z+9)+3z-(4z-9)=0

We add all the numbers together, and all the variables

3z-(-1z+9)-(4z-9)=0

We get rid of parentheses

3z+1z-4z-9+9=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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