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-(9/4)v+(4/5)=(7/8)
We move all terms to the left:
-(9/4)v+(4/5)-((7/8))=0
Domain of the equation: 4)v!=0We add all the numbers together, and all the variables
v!=0/1
v!=0
v∈R
-(+9/4)v+(+4/5)-((+7/8))=0
We multiply parentheses
-9v^2+(+4/5)-((+7/8))=0
We get rid of parentheses
-9v^2+4/5-((+7/8))=0
We calculate fractions
-9v^2+()/()+()/()=0
We add all the numbers together, and all the variables
-9v^2+2=0
a = -9; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-9)·2
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{2}}{2*-9}=\frac{0-6\sqrt{2}}{-18} =-\frac{6\sqrt{2}}{-18} =-\frac{\sqrt{2}}{-3} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{2}}{2*-9}=\frac{0+6\sqrt{2}}{-18} =\frac{6\sqrt{2}}{-18} =\frac{\sqrt{2}}{-3} $
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