-(9x-(16x+3))=3+(6x+10)

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Solution for -(9x-(16x+3))=3+(6x+10) equation: 



-(9x-(16x+3))=3+(6x+10)

We move all terms to the left:

-(9x-(16x+3))-(3+(6x+10))=0



We calculate terms in parentheses: -(9x-(16x+3)), so:

9x-(16x+3)

We get rid of parentheses

9x-16x-3

We add all the numbers together, and all the variables

-7x-3

Back to the equation:

-(-7x-3)





We calculate terms in parentheses: -(3+(6x+10)), so:

3+(6x+10)

determiningTheFunctionDomain
(6x+10)+3

We get rid of parentheses

6x+10+3

We add all the numbers together, and all the variables

6x+13

Back to the equation:

-(6x+13)



We get rid of parentheses

7x-6x+3-13=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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