-(9x-10)+11=12x+3(-2x+1/3)

Solution for -(9x-10)+11=12x+3(-2x+1/3) equation:

-(9x-10)+11=12x+3(-2x+1/3)

We move all terms to the left:

-(9x-10)+11-(12x+3(-2x+1/3))=0

We get rid of parentheses

-9x-(12x+3(-2x+1/3))+10+11=0

We multiply all the terms by the denominator


-9x*3))-(12x+3(-2x+1+10*3))+11*3))=0

We add all the numbers together, and all the variables

-9x*3))-(12x+3(-2x+31))+11*3))=0

We add all the numbers together, and all the variables

-2x-9x*3))-(12x+3(=0

Wy multiply elements

-27x^2-2x=0

a = -27; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-27)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-27}=\frac{0}{-54}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-27}=\frac{4}{-54}
=-2/27
$