-(9x-3)-(2x-5)+11=-8(x-1)-(6x+7)+3

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Solution for -(9x-3)-(2x-5)+11=-8(x-1)-(6x+7)+3 equation: 



-(9x-3)-(2x-5)+11=-8(x-1)-(6x+7)+3

We move all terms to the left:

-(9x-3)-(2x-5)+11-(-8(x-1)-(6x+7)+3)=0

We get rid of parentheses

-9x-2x-(-8(x-1)-(6x+7)+3)+3+5+11=0



We calculate terms in parentheses: -(-8(x-1)-(6x+7)+3), so:

-8(x-1)-(6x+7)+3

We multiply parentheses

-8x-(6x+7)+8+3

We get rid of parentheses

-8x-6x-7+8+3

We add all the numbers together, and all the variables

-14x+4

Back to the equation:

-(-14x+4)



We add all the numbers together, and all the variables

-11x-(-14x+4)+19=0

We get rid of parentheses

-11x+14x-4+19=0

We add all the numbers together, and all the variables

3x+15=0

We move all terms containing x to the left, all other terms to the right

3x=-15

x=-15/3

x=-5

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