-(a-1)-2(5a+1)=4(3a+4)

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Solution for -(a-1)-2(5a+1)=4(3a+4) equation: 



-(a-1)-2(5a+1)=4(3a+4)

We move all terms to the left:

-(a-1)-2(5a+1)-(4(3a+4))=0

We multiply parentheses

-(a-1)-10a-(4(3a+4))-2=0

We get rid of parentheses

-a-10a-(4(3a+4))+1-2=0



We calculate terms in parentheses: -(4(3a+4)), so:

4(3a+4)

We multiply parentheses

12a+16

Back to the equation:

-(12a+16)



We add all the numbers together, and all the variables

-11a-(12a+16)-1=0

We get rid of parentheses

-11a-12a-16-1=0

We add all the numbers together, and all the variables

-23a-17=0

We move all terms containing a to the left, all other terms to the right

-23a=17

a=17/-23

a=-17/23

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