-(b-4)+2(4b-7)=-2b+8b

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Solution for -(b-4)+2(4b-7)=-2b+8b equation: 



-(b-4)+2(4b-7)=-2b+8b

We move all terms to the left:

-(b-4)+2(4b-7)-(-2b+8b)=0

We add all the numbers together, and all the variables

-(b-4)+2(4b-7)-(+6b)=0

We multiply parentheses

-(b-4)+8b-(+6b)-14=0

We get rid of parentheses

-b+8b-6b+4-14=0

We add all the numbers together, and all the variables

b-10=0

We move all terms containing b to the left, all other terms to the right

b=10

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