-(c+2)+2c=6(2c-1)

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Solution for -(c+2)+2c=6(2c-1) equation:


Simplifying
-1(c + 2) + 2c = 6(2c + -1)

Reorder the terms:
-1(2 + c) + 2c = 6(2c + -1)
(2 * -1 + c * -1) + 2c = 6(2c + -1)
(-2 + -1c) + 2c = 6(2c + -1)

Combine like terms: -1c + 2c = 1c
-2 + 1c = 6(2c + -1)

Reorder the terms:
-2 + 1c = 6(-1 + 2c)
-2 + 1c = (-1 * 6 + 2c * 6)
-2 + 1c = (-6 + 12c)

Solving
-2 + 1c = -6 + 12c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-12c' to each side of the equation.
-2 + 1c + -12c = -6 + 12c + -12c

Combine like terms: 1c + -12c = -11c
-2 + -11c = -6 + 12c + -12c

Combine like terms: 12c + -12c = 0
-2 + -11c = -6 + 0
-2 + -11c = -6

Add '2' to each side of the equation.
-2 + 2 + -11c = -6 + 2

Combine like terms: -2 + 2 = 0
0 + -11c = -6 + 2
-11c = -6 + 2

Combine like terms: -6 + 2 = -4
-11c = -4

Divide each side by '-11'.
c = 0.3636363636

Simplifying
c = 0.3636363636

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