-(c-1)+5=2(c+3)-5

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Solution for -(c-1)+5=2(c+3)-5 equation: 



-(c-1)+5=2(c+3)-5

We move all terms to the left:

-(c-1)+5-(2(c+3)-5)=0

We get rid of parentheses

-c-(2(c+3)-5)+1+5=0



We calculate terms in parentheses: -(2(c+3)-5), so:

2(c+3)-5

We multiply parentheses

2c+6-5

We add all the numbers together, and all the variables

2c+1

Back to the equation:

-(2c+1)



We add all the numbers together, and all the variables

-1c-(2c+1)+6=0

We get rid of parentheses

-1c-2c-1+6=0

We add all the numbers together, and all the variables

-3c+5=0

We move all terms containing c to the left, all other terms to the right

-3c=-5

c=-5/-3

c=1+2/3

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