-(c-1)+5=2(c+3)-c

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Solution for -(c-1)+5=2(c+3)-c equation:



-(c-1)+5=2(c+3)-c
We move all terms to the left:
-(c-1)+5-(2(c+3)-c)=0
We get rid of parentheses
-c-(2(c+3)-c)+1+5=0
We calculate terms in parentheses: -(2(c+3)-c), so:
2(c+3)-c
We add all the numbers together, and all the variables
-1c+2(c+3)
We multiply parentheses
-1c+2c+6
We add all the numbers together, and all the variables
c+6
Back to the equation:
-(c+6)
We add all the numbers together, and all the variables
-1c-(c+6)+6=0
We get rid of parentheses
-1c-c-6+6=0
We add all the numbers together, and all the variables
-2c=0
c=0/-2
c=0

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