-(c-11)=2(-5+3c)

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Solution for -(c-11)=2(-5+3c) equation: 



-(c-11)=2(-5+3c)

We move all terms to the left:

-(c-11)-(2(-5+3c))=0

We add all the numbers together, and all the variables

-(c-11)-(2(3c-5))=0

We get rid of parentheses

-c-(2(3c-5))+11=0



We calculate terms in parentheses: -(2(3c-5)), so:

2(3c-5)

We multiply parentheses

6c-10

Back to the equation:

-(6c-10)



We add all the numbers together, and all the variables

-1c-(6c-10)+11=0

We get rid of parentheses

-1c-6c+10+11=0

We add all the numbers together, and all the variables

-7c+21=0

We move all terms containing c to the left, all other terms to the right

-7c=-21

c=-21/-7

c=+3

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