-(c-3)=-2(c+6)

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Solution for -(c-3)=-2(c+6) equation: 



-(c-3)=-2(c+6)

We move all terms to the left:

-(c-3)-(-2(c+6))=0

We get rid of parentheses

-c-(-2(c+6))+3=0



We calculate terms in parentheses: -(-2(c+6)), so:

-2(c+6)

We multiply parentheses

-2c-12

Back to the equation:

-(-2c-12)



We add all the numbers together, and all the variables

-1c-(-2c-12)+3=0

We get rid of parentheses

-1c+2c+12+3=0

We add all the numbers together, and all the variables

c+15=0

We move all terms containing c to the left, all other terms to the right

c=-15

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