-(d+4)+2(3-d)=-40

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Solution for -(d+4)+2(3-d)=-40 equation:



-(d+4)+2(3-d)=-40
We move all terms to the left:
-(d+4)+2(3-d)-(-40)=0
We add all the numbers together, and all the variables
-(d+4)+2(-1d+3)-(-40)=0
We add all the numbers together, and all the variables
-(d+4)+2(-1d+3)+40=0
We multiply parentheses
-(d+4)-2d+6+40=0
We get rid of parentheses
-d-2d-4+6+40=0
We add all the numbers together, and all the variables
-3d+42=0
We move all terms containing d to the left, all other terms to the right
-3d=-42
d=-42/-3
d=+14

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