-(k-2)-6k=3k-28

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Solution for -(k-2)-6k=3k-28 equation: 



-(k-2)-6k=3k-28

We move all terms to the left:

-(k-2)-6k-(3k-28)=0

We add all the numbers together, and all the variables

-6k-(k-2)-(3k-28)=0

We get rid of parentheses

-6k-k-3k+2+28=0

We add all the numbers together, and all the variables

-10k+30=0

We move all terms containing k to the left, all other terms to the right

-10k=-30

k=-30/-10

k=+3

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