-(n+1)-5(3-n)=1+n+1-3n

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Solution for -(n+1)-5(3-n)=1+n+1-3n equation: 



-(n+1)-5(3-n)=1+n+1-3n

We move all terms to the left:

-(n+1)-5(3-n)-(1+n+1-3n)=0

We add all the numbers together, and all the variables

-(n+1)-5(-1n+3)-(-2n+2)=0

We multiply parentheses

-(n+1)+5n-(-2n+2)-15=0

We get rid of parentheses

-n+5n+2n-1-2-15=0

We add all the numbers together, and all the variables

6n-18=0

We move all terms containing n to the left, all other terms to the right

6n=18

n=18/6

n=3

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