-(n+3)=2(n+3)

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Solution for -(n+3)=2(n+3) equation: 



-(n+3)=2(n+3)

We move all terms to the left:

-(n+3)-(2(n+3))=0

We get rid of parentheses

-n-(2(n+3))-3=0



We calculate terms in parentheses: -(2(n+3)), so:

2(n+3)

We multiply parentheses

2n+6

Back to the equation:

-(2n+6)



We add all the numbers together, and all the variables

-1n-(2n+6)-3=0

We get rid of parentheses

-1n-2n-6-3=0

We add all the numbers together, and all the variables

-3n-9=0

We move all terms containing n to the left, all other terms to the right

-3n=9

n=9/-3

n=-3

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