-(n-3)+5=4(n+2)-5

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Solution for -(n-3)+5=4(n+2)-5 equation: 


Simplifying
-1(n + -3) + 5 = 4(n + 2) + -5

Reorder the terms:
-1(-3 + n) + 5 = 4(n + 2) + -5
(-3 * -1 + n * -1) + 5 = 4(n + 2) + -5
(3 + -1n) + 5 = 4(n + 2) + -5

Reorder the terms:
3 + 5 + -1n = 4(n + 2) + -5

Combine like terms: 3 + 5 = 8
8 + -1n = 4(n + 2) + -5

Reorder the terms:
8 + -1n = 4(2 + n) + -5
8 + -1n = (2 * 4 + n * 4) + -5
8 + -1n = (8 + 4n) + -5

Reorder the terms:
8 + -1n = 8 + -5 + 4n

Combine like terms: 8 + -5 = 3
8 + -1n = 3 + 4n

Solving
8 + -1n = 3 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
8 + -1n + -4n = 3 + 4n + -4n

Combine like terms: -1n + -4n = -5n
8 + -5n = 3 + 4n + -4n

Combine like terms: 4n + -4n = 0
8 + -5n = 3 + 0
8 + -5n = 3

Add '-8' to each side of the equation.
8 + -8 + -5n = 3 + -8

Combine like terms: 8 + -8 = 0
0 + -5n = 3 + -8
-5n = 3 + -8

Combine like terms: 3 + -8 = -5
-5n = -5

Divide each side by '-5'.
n = 1

Simplifying
n = 1

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