-(n-3)-4(2n+1)=56

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Solution for -(n-3)-4(2n+1)=56 equation: 



-(n-3)-4(2n+1)=56

We move all terms to the left:

-(n-3)-4(2n+1)-(56)=0

We multiply parentheses

-(n-3)-8n-4-56=0

We get rid of parentheses

-n-8n+3-4-56=0

We add all the numbers together, and all the variables

-9n-57=0

We move all terms containing n to the left, all other terms to the right

-9n=57

n=57/-9

n=-6+1/3

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