-(n-3)=-(n+6)+3n

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Solution for -(n-3)=-(n+6)+3n equation: 



-(n-3)=-(n+6)+3n

We move all terms to the left:

-(n-3)-(-(n+6)+3n)=0

We get rid of parentheses

-n-(-(n+6)+3n)+3=0



We calculate terms in parentheses: -(-(n+6)+3n), so:

-(n+6)+3n

We add all the numbers together, and all the variables

3n-(n+6)

We get rid of parentheses

3n-n-6

We add all the numbers together, and all the variables

2n-6

Back to the equation:

-(2n-6)



We add all the numbers together, and all the variables

-1n-(2n-6)+3=0

We get rid of parentheses

-1n-2n+6+3=0

We add all the numbers together, and all the variables

-3n+9=0

We move all terms containing n to the left, all other terms to the right

-3n=-9

n=-9/-3

n=+3

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