-(n-6)-8=n(1+n)

Solution for -(n-6)-8=n(1+n) equation:

-(n-6)-8=n(1+n)

We move all terms to the left:

-(n-6)-8-(n(1+n))=0

We add all the numbers together, and all the variables

-(n-6)-(n(n+1))-8=0

We get rid of parentheses

-n-(n(n+1))+6-8=0


We calculate terms in parentheses: -(n(n+1)), so:

n(n+1)

We multiply parentheses

n^2+n

Back to the equation:

-(n^2+n)


We add all the numbers together, and all the variables

-1n-(n^2+n)-2=0

We get rid of parentheses

-n^2-1n-n-2=0

We add all the numbers together, and all the variables

-1n^2-2n-2=0

a = -1; b = -2; c = -2;
Δ = b2-4ac
Δ = -22-4·(-1)·(-2)
Δ = -4
Delta is less than zero, so there is no solution for the equation