-(n-6)-8=n(1+n)

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Solution for -(n-6)-8=n(1+n) equation:



-(n-6)-8=n(1+n)
We move all terms to the left:
-(n-6)-8-(n(1+n))=0
We add all the numbers together, and all the variables
-(n-6)-(n(n+1))-8=0
We get rid of parentheses
-n-(n(n+1))+6-8=0
We calculate terms in parentheses: -(n(n+1)), so:
n(n+1)
We multiply parentheses
n^2+n
Back to the equation:
-(n^2+n)
We add all the numbers together, and all the variables
-1n-(n^2+n)-2=0
We get rid of parentheses
-n^2-1n-n-2=0
We add all the numbers together, and all the variables
-1n^2-2n-2=0
a = -1; b = -2; c = -2;
Δ = b2-4ac
Δ = -22-4·(-1)·(-2)
Δ = -4
Delta is less than zero, so there is no solution for the equation

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