-(r/4)=(1/7)

Solution for -(r/4)=(1/7) equation:

-(r/4)=(1/7)

We move all terms to the left:

-(r/4)-((1/7))=0

We add all the numbers together, and all the variables

-(+r/4)-((+1/7))=0

We get rid of parentheses

-r/4-((+1/7))=0

We calculate fractions


(-7r^2)/()+()/()=0

We add all the numbers together, and all the variables

(-7r^2)/()+1=0

We multiply all the terms by the denominator


(-7r^2)+1*()=0

We add all the numbers together, and all the variables

(-7r^2)=0

We get rid of parentheses

-7r^2=0

a = -7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-7)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{-14}=0$