-(s+2)=4(s-1)

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Solution for -(s+2)=4(s-1) equation: 



-(s+2)=4(s-1)

We move all terms to the left:

-(s+2)-(4(s-1))=0

We get rid of parentheses

-s-(4(s-1))-2=0



We calculate terms in parentheses: -(4(s-1)), so:

4(s-1)

We multiply parentheses

4s-4

Back to the equation:

-(4s-4)



We add all the numbers together, and all the variables

-1s-(4s-4)-2=0

We get rid of parentheses

-1s-4s+4-2=0

We add all the numbers together, and all the variables

-5s+2=0

We move all terms containing s to the left, all other terms to the right

-5s=-2

s=-2/-5

s=2/5

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