-(v+1)=5(v-2)+3(-2v+3)

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Solution for -(v+1)=5(v-2)+3(-2v+3) equation: 



-(v+1)=5(v-2)+3(-2v+3)

We move all terms to the left:

-(v+1)-(5(v-2)+3(-2v+3))=0

We get rid of parentheses

-v-(5(v-2)+3(-2v+3))-1=0



We calculate terms in parentheses: -(5(v-2)+3(-2v+3)), so:

5(v-2)+3(-2v+3)

We multiply parentheses

5v-6v-10+9

We add all the numbers together, and all the variables

-1v-1

Back to the equation:

-(-1v-1)



We add all the numbers together, and all the variables

-1v-(-1v-1)-1=0

We get rid of parentheses

-1v+1v+1-1=0

We add all the numbers together, and all the variables

=0

v=0/1

v=0

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