-(v-3)+2(1+v)=(1+v)=v+4+7-2v

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Solution for -(v-3)+2(1+v)=(1+v)=v+4+7-2v equation: 



-(v-3)+2(1+v)=(1+v)=v+4+7-2v

We move all terms to the left:

-(v-3)+2(1+v)-((1+v))=0

We add all the numbers together, and all the variables

-(v-3)+2(v+1)-((v+1))=0

We multiply parentheses

-(v-3)+2v-((v+1))+2=0

We get rid of parentheses

-v+2v-((v+1))+3+2=0



We calculate terms in parentheses: -((v+1)), so:

(v+1)

We get rid of parentheses

v+1

Back to the equation:

-(v+1)



We add all the numbers together, and all the variables

v-(v+1)+5=0

We get rid of parentheses

v-v-1+5=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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