-(x+1)+4=(x-5)/2

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Solution for -(x+1)+4=(x-5)/2 equation:



-(x+1)+4=(x-5)/2
We move all terms to the left:
-(x+1)+4-((x-5)/2)=0
We get rid of parentheses
-x-((x-5)/2)-1+4=0
We multiply all the terms by the denominator
-x*2)-((x-5)-1*2)+4*2)=0
We add all the numbers together, and all the variables
-x*2)-((x-5)=0
Wy multiply elements
-2x^2=0
a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-4}=0$

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