-(x+2)(x-1)=3

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Solution for -(x+2)(x-1)=3 equation: 



-(x+2)(x-1)=3

We move all terms to the left:

-(x+2)(x-1)-(3)=0

We multiply parentheses ..

-(+x^2-1x+2x-2)-3=0

We get rid of parentheses

-x^2+1x-2x+2-3=0

We add all the numbers together, and all the variables

-1x^2-1x-1=0

a = -1; b = -1; c = -1;
Δ = b2-4ac
Δ = -12-4·(-1)·(-1)
Δ = -3
Delta is less than zero, so there is no solution for the equation

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